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5(x+2)=2(3x-10)
We move all terms to the left:
5(x+2)-(2(3x-10))=0
We multiply parentheses
5x-(2(3x-10))+10=0
We calculate terms in parentheses: -(2(3x-10)), so:We get rid of parentheses
2(3x-10)
We multiply parentheses
6x-20
Back to the equation:
-(6x-20)
5x-6x+20+10=0
We add all the numbers together, and all the variables
-1x+30=0
We move all terms containing x to the left, all other terms to the right
-x=-30
x=-30/-1
x=+30
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