5(x+2)=2-(x-4)

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Solution for 5(x+2)=2-(x-4) equation: 



5(x+2)=2-(x-4)

We move all terms to the left:

5(x+2)-(2-(x-4))=0

We multiply parentheses

5x-(2-(x-4))+10=0



We calculate terms in parentheses: -(2-(x-4)), so:

2-(x-4)

determiningTheFunctionDomain
-(x-4)+2

We get rid of parentheses

-x+4+2

We add all the numbers together, and all the variables

-1x+6

Back to the equation:

-(-1x+6)



We get rid of parentheses

5x+1x-6+10=0

We add all the numbers together, and all the variables

6x+4=0

We move all terms containing x to the left, all other terms to the right

6x=-4

x=-4/6

x=-2/3

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