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5(x+2)=20+3(x+2)
We move all terms to the left:
5(x+2)-(20+3(x+2))=0
We multiply parentheses
5x-(20+3(x+2))+10=0
We calculate terms in parentheses: -(20+3(x+2)), so:We get rid of parentheses
20+3(x+2)
determiningTheFunctionDomain 3(x+2)+20
We multiply parentheses
3x+6+20
We add all the numbers together, and all the variables
3x+26
Back to the equation:
-(3x+26)
5x-3x-26+10=0
We add all the numbers together, and all the variables
2x-16=0
We move all terms containing x to the left, all other terms to the right
2x=16
x=16/2
x=8
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