5(x+2)=20+3(x+2)

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Solution for 5(x+2)=20+3(x+2) equation: 



5(x+2)=20+3(x+2)

We move all terms to the left:

5(x+2)-(20+3(x+2))=0

We multiply parentheses

5x-(20+3(x+2))+10=0



We calculate terms in parentheses: -(20+3(x+2)), so:

20+3(x+2)

determiningTheFunctionDomain
3(x+2)+20

We multiply parentheses

3x+6+20

We add all the numbers together, and all the variables

3x+26

Back to the equation:

-(3x+26)



We get rid of parentheses

5x-3x-26+10=0

We add all the numbers together, and all the variables

2x-16=0

We move all terms containing x to the left, all other terms to the right

2x=16

x=16/2

x=8

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