5(x+2)=3(-2x-4)

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Solution for 5(x+2)=3(-2x-4) equation: 



5(x+2)=3(-2x-4)

We move all terms to the left:

5(x+2)-(3(-2x-4))=0

We multiply parentheses

5x-(3(-2x-4))+10=0



We calculate terms in parentheses: -(3(-2x-4)), so:

3(-2x-4)

We multiply parentheses

-6x-12

Back to the equation:

-(-6x-12)



We get rid of parentheses

5x+6x+12+10=0

We add all the numbers together, and all the variables

11x+22=0

We move all terms containing x to the left, all other terms to the right

11x=-22

x=-22/11

x=-2

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