5(x+2)=3(x-5)+29

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Solution for 5(x+2)=3(x-5)+29 equation: 



5(x+2)=3(x-5)+29

We move all terms to the left:

5(x+2)-(3(x-5)+29)=0

We multiply parentheses

5x-(3(x-5)+29)+10=0



We calculate terms in parentheses: -(3(x-5)+29), so:

3(x-5)+29

We multiply parentheses

3x-15+29

We add all the numbers together, and all the variables

3x+14

Back to the equation:

-(3x+14)



We get rid of parentheses

5x-3x-14+10=0

We add all the numbers together, and all the variables

2x-4=0

We move all terms containing x to the left, all other terms to the right

2x=4

x=4/2

x=2

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