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5(x+2)=3(x-5)=6
We move all terms to the left:
5(x+2)-(3(x-5))=0
We multiply parentheses
5x-(3(x-5))+10=0
We calculate terms in parentheses: -(3(x-5)), so:We get rid of parentheses
3(x-5)
We multiply parentheses
3x-15
Back to the equation:
-(3x-15)
5x-3x+15+10=0
We add all the numbers together, and all the variables
2x+25=0
We move all terms containing x to the left, all other terms to the right
2x=-25
x=-25/2
x=-12+1/2
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