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5(x+2)=3x-(6-x)
We move all terms to the left:
5(x+2)-(3x-(6-x))=0
We add all the numbers together, and all the variables
5(x+2)-(3x-(-1x+6))=0
We multiply parentheses
5x-(3x-(-1x+6))+10=0
We calculate terms in parentheses: -(3x-(-1x+6)), so:We get rid of parentheses
3x-(-1x+6)
We get rid of parentheses
3x+1x-6
We add all the numbers together, and all the variables
4x-6
Back to the equation:
-(4x-6)
5x-4x+6+10=0
We add all the numbers together, and all the variables
x+16=0
We move all terms containing x to the left, all other terms to the right
x=-16
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