5(x+2)=4(x+3)=

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Solution for 5(x+2)=4(x+3)= equation: 



5(x+2)=4(x+3)=

We move all terms to the left:

5(x+2)-(4(x+3))=0

We multiply parentheses

5x-(4(x+3))+10=0



We calculate terms in parentheses: -(4(x+3)), so:

4(x+3)

We multiply parentheses

4x+12

Back to the equation:

-(4x+12)



We get rid of parentheses

5x-4x-12+10=0

We add all the numbers together, and all the variables

x-2=0

We move all terms containing x to the left, all other terms to the right

x=2

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