5(x+2)=4(x+4)-5

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Solution for 5(x+2)=4(x+4)-5 equation:



5(x+2)=4(x+4)-5
We move all terms to the left:
5(x+2)-(4(x+4)-5)=0
We multiply parentheses
5x-(4(x+4)-5)+10=0
We calculate terms in parentheses: -(4(x+4)-5), so:
4(x+4)-5
We multiply parentheses
4x+16-5
We add all the numbers together, and all the variables
4x+11
Back to the equation:
-(4x+11)
We get rid of parentheses
5x-4x-11+10=0
We add all the numbers together, and all the variables
x-1=0
We move all terms containing x to the left, all other terms to the right
x=1

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