5(x+2)=41

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Solution for 5(x+2)=41 equation: 



5(x+2)=41

We move all terms to the left:

5(x+2)-(41)=0

We multiply parentheses

5x+10-41=0

We add all the numbers together, and all the variables

5x-31=0

We move all terms containing x to the left, all other terms to the right

5x=31

x=31/5

x=6+1/5

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