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5(x+2)=5(x+5)-15
We move all terms to the left:
5(x+2)-(5(x+5)-15)=0
We multiply parentheses
5x-(5(x+5)-15)+10=0
We calculate terms in parentheses: -(5(x+5)-15), so:We get rid of parentheses
5(x+5)-15
We multiply parentheses
5x+25-15
We add all the numbers together, and all the variables
5x+10
Back to the equation:
-(5x+10)
5x-5x-10+10=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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