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5(x+2)=x/2+9x
We move all terms to the left:
5(x+2)-(x/2+9x)=0
Domain of the equation: 2+9x)!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
9x)!=-2
x!=-2/1
x!=-2
x∈R
5(x+2)-(+9x+x/2)=0
We multiply parentheses
5x-(+9x+x/2)+10=0
We get rid of parentheses
5x-9x-x/2+10=0
We multiply all the terms by the denominator
5x*2-9x*2-x+10*2=0
We add all the numbers together, and all the variables
-1x+5x*2-9x*2+20=0
Wy multiply elements
-1x+10x-18x+20=0
We add all the numbers together, and all the variables
-9x+20=0
We move all terms containing x to the left, all other terms to the right
-9x=-20
x=-20/-9
x=2+2/9
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