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5(x+3)(x+5)=0
We multiply parentheses ..
5(+x^2+5x+3x+15)=0
We multiply parentheses
5x^2+25x+15x+75=0
We add all the numbers together, and all the variables
5x^2+40x+75=0
a = 5; b = 40; c = +75;
Δ = b2-4ac
Δ = 402-4·5·75
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{100}=10$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(40)-10}{2*5}=\frac{-50}{10} =-5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(40)+10}{2*5}=\frac{-30}{10} =-3 $
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