5(x+3)+0=3(x-2)+6

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Solution for 5(x+3)+0=3(x-2)+6 equation:



5(x+3)+0=3(x-2)+6
We move all terms to the left:
5(x+3)+0-(3(x-2)+6)=0
We add all the numbers together, and all the variables
5(x+3)-(3(x-2)+6)=0
We multiply parentheses
5x-(3(x-2)+6)+15=0
We calculate terms in parentheses: -(3(x-2)+6), so:
3(x-2)+6
We multiply parentheses
3x-6+6
We add all the numbers together, and all the variables
3x
Back to the equation:
-(3x)
We add all the numbers together, and all the variables
2x+15=0
We move all terms containing x to the left, all other terms to the right
2x=-15
x=-15/2
x=-7+1/2

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