5(x+3)+0=3(x-2)+6

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Solution for 5(x+3)+0=3(x-2)+6 equation: 



5(x+3)+0=3(x-2)+6

We move all terms to the left:

5(x+3)+0-(3(x-2)+6)=0

We add all the numbers together, and all the variables

5(x+3)-(3(x-2)+6)=0

We multiply parentheses

5x-(3(x-2)+6)+15=0



We calculate terms in parentheses: -(3(x-2)+6), so:

3(x-2)+6

We multiply parentheses

3x-6+6

We add all the numbers together, and all the variables

3x

Back to the equation:

-(3x)



We add all the numbers together, and all the variables

2x+15=0

We move all terms containing x to the left, all other terms to the right

2x=-15

x=-15/2

x=-7+1/2

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