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5(x+3)+3x=2x+27
We move all terms to the left:
5(x+3)+3x-(2x+27)=0
We add all the numbers together, and all the variables
3x+5(x+3)-(2x+27)=0
We multiply parentheses
3x+5x-(2x+27)+15=0
We get rid of parentheses
3x+5x-2x-27+15=0
We add all the numbers together, and all the variables
6x-12=0
We move all terms containing x to the left, all other terms to the right
6x=12
x=12/6
x=2
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