5(x+3)+4x-3=-(2x-4)2x-4)+2

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Solution for 5(x+3)+4x-3=-(2x-4)2x-4)+2 equation: 



5(x+3)+4x-3=-(2x-4)2x-4)+2

We move all terms to the left:

5(x+3)+4x-3-(-(2x-4)2x-4)+2)=0

We add all the numbers together, and all the variables

4x+5(x+3)-(-(2x-4)2x-4)=0

We multiply parentheses

4x+5x-(-(2x-4)2x-4)+15=0



We calculate terms in parentheses: -(-(2x-4)2x-4), so:

-(2x-4)2x-4

We multiply parentheses

-4x^2+8x-4

Back to the equation:

-(-4x^2+8x-4)



We add all the numbers together, and all the variables

-(-4x^2+8x-4)+9x+15=0

We get rid of parentheses

4x^2-8x+9x+4+15=0

We add all the numbers together, and all the variables

4x^2+x+19=0

a = 4; b = 1; c = +19;
Δ = b2-4ac
Δ = 12-4·4·19
Δ = -303
Delta is less than zero, so there is no solution for the equation

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