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5(x+3)+4x=3(3x+1)
We move all terms to the left:
5(x+3)+4x-(3(3x+1))=0
We add all the numbers together, and all the variables
4x+5(x+3)-(3(3x+1))=0
We multiply parentheses
4x+5x-(3(3x+1))+15=0
We calculate terms in parentheses: -(3(3x+1)), so:We add all the numbers together, and all the variables
3(3x+1)
We multiply parentheses
9x+3
Back to the equation:
-(9x+3)
9x-(9x+3)+15=0
We get rid of parentheses
9x-9x-3+15=0
We add all the numbers together, and all the variables
12!=0
There is no solution for this equation
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