5(x+3)+6x=3(2x+1)-4x

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Solution for 5(x+3)+6x=3(2x+1)-4x equation: 



5(x+3)+6x=3(2x+1)-4x

We move all terms to the left:

5(x+3)+6x-(3(2x+1)-4x)=0

We add all the numbers together, and all the variables

6x+5(x+3)-(3(2x+1)-4x)=0

We multiply parentheses

6x+5x-(3(2x+1)-4x)+15=0



We calculate terms in parentheses: -(3(2x+1)-4x), so:

3(2x+1)-4x

We add all the numbers together, and all the variables

-4x+3(2x+1)

We multiply parentheses

-4x+6x+3

We add all the numbers together, and all the variables

2x+3

Back to the equation:

-(2x+3)



We add all the numbers together, and all the variables

11x-(2x+3)+15=0

We get rid of parentheses

11x-2x-3+15=0

We add all the numbers together, and all the variables

9x+12=0

We move all terms containing x to the left, all other terms to the right

9x=-12

x=-12/9

x=-1+1/3

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