5(x+3)+7(x-4)=29

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Solution for 5(x+3)+7(x-4)=29 equation: 



5(x+3)+7(x-4)=29

We move all terms to the left:

5(x+3)+7(x-4)-(29)=0

We multiply parentheses

5x+7x+15-28-29=0

We add all the numbers together, and all the variables

12x-42=0

We move all terms containing x to the left, all other terms to the right

12x=42

x=42/12

x=3+1/2

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