5(x+3)+7(x-5)=2(x+1)

Solution for 5(x+3)+7(x-5)=2(x+1) equation:

Simplifying
5(x + 3) + 7(x + -5) = 2(x + 1)

Reorder the terms:
5(3 + x) + 7(x + -5) = 2(x + 1)
(3 * 5 + x * 5) + 7(x + -5) = 2(x + 1)
(15 + 5x) + 7(x + -5) = 2(x + 1)

Reorder the terms:
15 + 5x + 7(-5 + x) = 2(x + 1)
15 + 5x + (-5 * 7 + x * 7) = 2(x + 1)
15 + 5x + (-35 + 7x) = 2(x + 1)

Reorder the terms:
15 + -35 + 5x + 7x = 2(x + 1)

Combine like terms: 15 + -35 = -20
-20 + 5x + 7x = 2(x + 1)

Combine like terms: 5x + 7x = 12x
-20 + 12x = 2(x + 1)

Reorder the terms:
-20 + 12x = 2(1 + x)
-20 + 12x = (1 * 2 + x * 2)
-20 + 12x = (2 + 2x)

Solving
-20 + 12x = 2 + 2x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-2x' to each side of the equation.
-20 + 12x + -2x = 2 + 2x + -2x

Combine like terms: 12x + -2x = 10x
-20 + 10x = 2 + 2x + -2x

Combine like terms: 2x + -2x = 0
-20 + 10x = 2 + 0
-20 + 10x = 2

Add '20' to each side of the equation.
-20 + 20 + 10x = 2 + 20

Combine like terms: -20 + 20 = 0
0 + 10x = 2 + 20
10x = 2 + 20

Combine like terms: 2 + 20 = 22
10x = 22

Divide each side by '10'.
x = 2.2

Simplifying
x = 2.2