5(x+3)+7x=3(x-10)

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Solution for 5(x+3)+7x=3(x-10) equation: 



5(x+3)+7x=3(x-10)

We move all terms to the left:

5(x+3)+7x-(3(x-10))=0

We add all the numbers together, and all the variables

7x+5(x+3)-(3(x-10))=0

We multiply parentheses

7x+5x-(3(x-10))+15=0



We calculate terms in parentheses: -(3(x-10)), so:

3(x-10)

We multiply parentheses

3x-30

Back to the equation:

-(3x-30)



We add all the numbers together, and all the variables

12x-(3x-30)+15=0

We get rid of parentheses

12x-3x+30+15=0

We add all the numbers together, and all the variables

9x+45=0

We move all terms containing x to the left, all other terms to the right

9x=-45

x=-45/9

x=-5

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