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5(x+3)+9=3(x-2)+10
We move all terms to the left:
5(x+3)+9-(3(x-2)+10)=0
We multiply parentheses
5x-(3(x-2)+10)+15+9=0
We calculate terms in parentheses: -(3(x-2)+10), so:We add all the numbers together, and all the variables
3(x-2)+10
We multiply parentheses
3x-6+10
We add all the numbers together, and all the variables
3x+4
Back to the equation:
-(3x+4)
5x-(3x+4)+24=0
We get rid of parentheses
5x-3x-4+24=0
We add all the numbers together, and all the variables
2x+20=0
We move all terms containing x to the left, all other terms to the right
2x=-20
x=-20/2
x=-10
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