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5(x+3)+x=2(x+5)-8
We move all terms to the left:
5(x+3)+x-(2(x+5)-8)=0
We add all the numbers together, and all the variables
x+5(x+3)-(2(x+5)-8)=0
We multiply parentheses
x+5x-(2(x+5)-8)+15=0
We calculate terms in parentheses: -(2(x+5)-8), so:We add all the numbers together, and all the variables
2(x+5)-8
We multiply parentheses
2x+10-8
We add all the numbers together, and all the variables
2x+2
Back to the equation:
-(2x+2)
6x-(2x+2)+15=0
We get rid of parentheses
6x-2x-2+15=0
We add all the numbers together, and all the variables
4x+13=0
We move all terms containing x to the left, all other terms to the right
4x=-13
x=-13/4
x=-3+1/4
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