5(x+3)-(6(x-4)+2(3x-1))=2(4-x)-2

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Solution for 5(x+3)-(6(x-4)+2(3x-1))=2(4-x)-2 equation: 



5(x+3)-(6(x-4)+2(3x-1))=2(4-x)-2

We move all terms to the left:

5(x+3)-(6(x-4)+2(3x-1))-(2(4-x)-2)=0

We add all the numbers together, and all the variables

5(x+3)-(6(x-4)+2(3x-1))-(2(-1x+4)-2)=0

We multiply parentheses

5x-(6(x-4)+2(3x-1))-(2(-1x+4)-2)+15=0



We calculate terms in parentheses: -(6(x-4)+2(3x-1)), so:

6(x-4)+2(3x-1)

We multiply parentheses

6x+6x-24-2

We add all the numbers together, and all the variables

12x-26

Back to the equation:

-(12x-26)





We calculate terms in parentheses: -(2(-1x+4)-2), so:

2(-1x+4)-2

We multiply parentheses

-2x+8-2

We add all the numbers together, and all the variables

-2x+6

Back to the equation:

-(-2x+6)



We get rid of parentheses

5x-12x+2x+26-6+15=0

We add all the numbers together, and all the variables

-5x+35=0

We move all terms containing x to the left, all other terms to the right

-5x=-35

x=-35/-5

x=+7

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