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5(x+3)-1=3(x+4)+6
We move all terms to the left:
5(x+3)-1-(3(x+4)+6)=0
We multiply parentheses
5x-(3(x+4)+6)+15-1=0
We calculate terms in parentheses: -(3(x+4)+6), so:We add all the numbers together, and all the variables
3(x+4)+6
We multiply parentheses
3x+12+6
We add all the numbers together, and all the variables
3x+18
Back to the equation:
-(3x+18)
5x-(3x+18)+14=0
We get rid of parentheses
5x-3x-18+14=0
We add all the numbers together, and all the variables
2x-4=0
We move all terms containing x to the left, all other terms to the right
2x=4
x=4/2
x=2
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