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5(x+3)-2(x-6)=6(x+3)
We move all terms to the left:
5(x+3)-2(x-6)-(6(x+3))=0
We multiply parentheses
5x-2x-(6(x+3))+15+12=0
We calculate terms in parentheses: -(6(x+3)), so:We add all the numbers together, and all the variables
6(x+3)
We multiply parentheses
6x+18
Back to the equation:
-(6x+18)
3x-(6x+18)+27=0
We get rid of parentheses
3x-6x-18+27=0
We add all the numbers together, and all the variables
-3x+9=0
We move all terms containing x to the left, all other terms to the right
-3x=-9
x=-9/-3
x=+3
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