5(x+3)-5(x*2-1)=x*2+7(3-x)-1

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Solution for 5(x+3)-5(x*2-1)=x*2+7(3-x)-1 equation: 



5(x+3)-5(x*2-1)=x*2+7(3-x)-1

We move all terms to the left:

5(x+3)-5(x*2-1)-(x*2+7(3-x)-1)=0

We add all the numbers together, and all the variables

5(x+3)-5(x*2-1)-(x*2+7(-1x+3)-1)=0

We multiply parentheses

5x-10x-(x*2+7(-1x+3)-1)+15+5=0



We calculate terms in parentheses: -(x*2+7(-1x+3)-1), so:

x*2+7(-1x+3)-1

We multiply parentheses

x*2-7x+21-1

Wy multiply elements

2x-7x+21-1

We add all the numbers together, and all the variables

-5x+20

Back to the equation:

-(-5x+20)



We add all the numbers together, and all the variables

-5x-(-5x+20)+20=0

We get rid of parentheses

-5x+5x-20+20=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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