5(x+3)-6=4-1/2(-10x-10)

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Solution for 5(x+3)-6=4-1/2(-10x-10) equation: 



5(x+3)-6=4-1/2(-10x-10)

We move all terms to the left:

5(x+3)-6-(4-1/2(-10x-10))=0



Domain of the equation: 2(-10x-10))!=0

x∈R



We multiply parentheses

5x-(4-1/2(-10x-10))+15-6=0

We multiply all the terms by the denominator


5x*2(-10x-10))-(4+15*2(-10x-10))-6*2(-10x-1-10))=0

We add all the numbers together, and all the variables

5x*2(-10x-10))-(4+15*2(-10x-10))-6*2(-10x-11))=0

We add all the numbers together, and all the variables

-10x+5x*2(-10x-10))-(4+15*2(-10x-10))-6*2(=0

Wy multiply elements

10x^2(-+60x^2(--10x=0

We use the square of the difference formula

10x^2(-60x^2(+10x=0

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