5(x+3)-8=4(x+3)+x-5

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Solution for 5(x+3)-8=4(x+3)+x-5 equation: 



5(x+3)-8=4(x+3)+x-5

We move all terms to the left:

5(x+3)-8-(4(x+3)+x-5)=0

We multiply parentheses

5x-(4(x+3)+x-5)+15-8=0



We calculate terms in parentheses: -(4(x+3)+x-5), so:

4(x+3)+x-5

We add all the numbers together, and all the variables

x+4(x+3)-5

We multiply parentheses

x+4x+12-5

We add all the numbers together, and all the variables

5x+7

Back to the equation:

-(5x+7)



We add all the numbers together, and all the variables

5x-(5x+7)+7=0

We get rid of parentheses

5x-5x-7+7=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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