5(x+3)/2=8(x-4)/3

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Solution for 5(x+3)/2=8(x-4)/3 equation: 



5(x+3)/2=8(x-4)/3

We move all terms to the left:

5(x+3)/2-(8(x-4)/3)=0

We calculate fractions


5x/()+(-(8(x-4)*2)/()=0



We calculate terms in parentheses: +(-(8(x-4)*2)/(), so:

-(8(x-4)*2)/(

We multiply all the terms by the denominator


-(8(x-4)*2)



We calculate terms in parentheses: -(8(x-4)*2), so:

8(x-4)*2

We multiply parentheses

16x-64

Back to the equation:

-(16x-64)



We get rid of parentheses

-16x+64

Back to the equation:

+(-16x+64)



We get rid of parentheses

5x/()-16x+64=0

We multiply all the terms by the denominator


5x-16x*()+64*()=0

We add all the numbers together, and all the variables

5x-16x*()=0

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