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5(x+3)=(3x-4)
We move all terms to the left:
5(x+3)-((3x-4))=0
We multiply parentheses
5x-((3x-4))+15=0
We calculate terms in parentheses: -((3x-4)), so:We get rid of parentheses
(3x-4)
We get rid of parentheses
3x-4
Back to the equation:
-(3x-4)
5x-3x+4+15=0
We add all the numbers together, and all the variables
2x+19=0
We move all terms containing x to the left, all other terms to the right
2x=-19
x=-19/2
x=-9+1/2
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