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5(x+3)=2(2x+1)-2(3x-1)+3(2x+1)
We move all terms to the left:
5(x+3)-(2(2x+1)-2(3x-1)+3(2x+1))=0
We multiply parentheses
5x-(2(2x+1)-2(3x-1)+3(2x+1))+15=0
We calculate terms in parentheses: -(2(2x+1)-2(3x-1)+3(2x+1)), so:We get rid of parentheses
2(2x+1)-2(3x-1)+3(2x+1)
We multiply parentheses
4x-6x+6x+2+2+3
We add all the numbers together, and all the variables
4x+7
Back to the equation:
-(4x+7)
5x-4x-7+15=0
We add all the numbers together, and all the variables
x+8=0
We move all terms containing x to the left, all other terms to the right
x=-8
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