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5(x+3)=2x+35(x+3)=2x+3
We move all terms to the left:
5(x+3)-(2x+35(x+3))=0
We multiply parentheses
5x-(2x+35(x+3))+15=0
We calculate terms in parentheses: -(2x+35(x+3)), so:We get rid of parentheses
2x+35(x+3)
We multiply parentheses
2x+35x+105
We add all the numbers together, and all the variables
37x+105
Back to the equation:
-(37x+105)
5x-37x-105+15=0
We add all the numbers together, and all the variables
-32x-90=0
We move all terms containing x to the left, all other terms to the right
-32x=90
x=90/-32
x=-2+13/16
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