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5(x+3)=3(2x-1)+6
We move all terms to the left:
5(x+3)-(3(2x-1)+6)=0
We multiply parentheses
5x-(3(2x-1)+6)+15=0
We calculate terms in parentheses: -(3(2x-1)+6), so:We get rid of parentheses
3(2x-1)+6
We multiply parentheses
6x-3+6
We add all the numbers together, and all the variables
6x+3
Back to the equation:
-(6x+3)
5x-6x-3+15=0
We add all the numbers together, and all the variables
-1x+12=0
We move all terms containing x to the left, all other terms to the right
-x=-12
x=-12/-1
x=+12
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