5(x+3)=3+2(3x-5)

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Solution for 5(x+3)=3+2(3x-5) equation: 



5(x+3)=3+2(3x-5)

We move all terms to the left:

5(x+3)-(3+2(3x-5))=0

We multiply parentheses

5x-(3+2(3x-5))+15=0



We calculate terms in parentheses: -(3+2(3x-5)), so:

3+2(3x-5)

determiningTheFunctionDomain
2(3x-5)+3

We multiply parentheses

6x-10+3

We add all the numbers together, and all the variables

6x-7

Back to the equation:

-(6x-7)



We get rid of parentheses

5x-6x+7+15=0

We add all the numbers together, and all the variables

-1x+22=0

We move all terms containing x to the left, all other terms to the right

-x=-22

x=-22/-1

x=+22

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