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5(x+3)=4(x+5)
We move all terms to the left:
5(x+3)-(4(x+5))=0
We multiply parentheses
5x-(4(x+5))+15=0
We calculate terms in parentheses: -(4(x+5)), so:We get rid of parentheses
4(x+5)
We multiply parentheses
4x+20
Back to the equation:
-(4x+20)
5x-4x-20+15=0
We add all the numbers together, and all the variables
x-5=0
We move all terms containing x to the left, all other terms to the right
x=5
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