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5(x+3)=5(2x-5)
We move all terms to the left:
5(x+3)-(5(2x-5))=0
We multiply parentheses
5x-(5(2x-5))+15=0
We calculate terms in parentheses: -(5(2x-5)), so:We get rid of parentheses
5(2x-5)
We multiply parentheses
10x-25
Back to the equation:
-(10x-25)
5x-10x+25+15=0
We add all the numbers together, and all the variables
-5x+40=0
We move all terms containing x to the left, all other terms to the right
-5x=-40
x=-40/-5
x=+8
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