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5(x+3)=6-3(2x+4)
We move all terms to the left:
5(x+3)-(6-3(2x+4))=0
We multiply parentheses
5x-(6-3(2x+4))+15=0
We calculate terms in parentheses: -(6-3(2x+4)), so:We get rid of parentheses
6-3(2x+4)
determiningTheFunctionDomain -3(2x+4)+6
We multiply parentheses
-6x-12+6
We add all the numbers together, and all the variables
-6x-6
Back to the equation:
-(-6x-6)
5x+6x+6+15=0
We add all the numbers together, and all the variables
11x+21=0
We move all terms containing x to the left, all other terms to the right
11x=-21
x=-21/11
x=-1+10/11
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