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5(x+3)=7(x-5)
We move all terms to the left:
5(x+3)-(7(x-5))=0
We multiply parentheses
5x-(7(x-5))+15=0
We calculate terms in parentheses: -(7(x-5)), so:We get rid of parentheses
7(x-5)
We multiply parentheses
7x-35
Back to the equation:
-(7x-35)
5x-7x+35+15=0
We add all the numbers together, and all the variables
-2x+50=0
We move all terms containing x to the left, all other terms to the right
-2x=-50
x=-50/-2
x=+25
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