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5(x+4)(2x-9)=0
We multiply parentheses ..
5(+2x^2-9x+8x-36)=0
We multiply parentheses
10x^2-45x+40x-180=0
We add all the numbers together, and all the variables
10x^2-5x-180=0
a = 10; b = -5; c = -180;
Δ = b2-4ac
Δ = -52-4·10·(-180)
Δ = 7225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{7225}=85$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-85}{2*10}=\frac{-80}{20} =-4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+85}{2*10}=\frac{90}{20} =4+1/2 $
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