5(x+4)+12=2(x-3-1)

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Solution for 5(x+4)+12=2(x-3-1) equation: 



5(x+4)+12=2(x-3-1)

We move all terms to the left:

5(x+4)+12-(2(x-3-1))=0

We add all the numbers together, and all the variables

5(x+4)-(2(x-4))+12=0

We multiply parentheses

5x-(2(x-4))+20+12=0



We calculate terms in parentheses: -(2(x-4)), so:

2(x-4)

We multiply parentheses

2x-8

Back to the equation:

-(2x-8)



We add all the numbers together, and all the variables

5x-(2x-8)+32=0

We get rid of parentheses

5x-2x+8+32=0

We add all the numbers together, and all the variables

3x+40=0

We move all terms containing x to the left, all other terms to the right

3x=-40

x=-40/3

x=-13+1/3

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