5(x+4)+2=-8(x-5)-11

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Solution for 5(x+4)+2=-8(x-5)-11 equation: 



5(x+4)+2=-8(x-5)-11

We move all terms to the left:

5(x+4)+2-(-8(x-5)-11)=0

We multiply parentheses

5x-(-8(x-5)-11)+20+2=0



We calculate terms in parentheses: -(-8(x-5)-11), so:

-8(x-5)-11

We multiply parentheses

-8x+40-11

We add all the numbers together, and all the variables

-8x+29

Back to the equation:

-(-8x+29)



We add all the numbers together, and all the variables

5x-(-8x+29)+22=0

We get rid of parentheses

5x+8x-29+22=0

We add all the numbers together, and all the variables

13x-7=0

We move all terms containing x to the left, all other terms to the right

13x=7

x=7/13

x=7/13

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