5(x+4)+2x=4(x-5)+11x

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Solution for 5(x+4)+2x=4(x-5)+11x equation: 



5(x+4)+2x=4(x-5)+11x

We move all terms to the left:

5(x+4)+2x-(4(x-5)+11x)=0

We add all the numbers together, and all the variables

2x+5(x+4)-(4(x-5)+11x)=0

We multiply parentheses

2x+5x-(4(x-5)+11x)+20=0



We calculate terms in parentheses: -(4(x-5)+11x), so:

4(x-5)+11x

We add all the numbers together, and all the variables

11x+4(x-5)

We multiply parentheses

11x+4x-20

We add all the numbers together, and all the variables

15x-20

Back to the equation:

-(15x-20)



We add all the numbers together, and all the variables

7x-(15x-20)+20=0

We get rid of parentheses

7x-15x+20+20=0

We add all the numbers together, and all the variables

-8x+40=0

We move all terms containing x to the left, all other terms to the right

-8x=-40

x=-40/-8

x=+5

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