5(x+4)+7=7-2(x+4)

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Solution for 5(x+4)+7=7-2(x+4) equation: 



5(x+4)+7=7-2(x+4)

We move all terms to the left:

5(x+4)+7-(7-2(x+4))=0

We multiply parentheses

5x-(7-2(x+4))+20+7=0



We calculate terms in parentheses: -(7-2(x+4)), so:

7-2(x+4)

determiningTheFunctionDomain
-2(x+4)+7

We multiply parentheses

-2x-8+7

We add all the numbers together, and all the variables

-2x-1

Back to the equation:

-(-2x-1)



We add all the numbers together, and all the variables

5x-(-2x-1)+27=0

We get rid of parentheses

5x+2x+1+27=0

We add all the numbers together, and all the variables

7x+28=0

We move all terms containing x to the left, all other terms to the right

7x=-28

x=-28/7

x=-4

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