5(x+4)+x=3(x+2)-2

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Solution for 5(x+4)+x=3(x+2)-2 equation: 



5(x+4)+x=3(x+2)-2

We move all terms to the left:

5(x+4)+x-(3(x+2)-2)=0

We add all the numbers together, and all the variables

x+5(x+4)-(3(x+2)-2)=0

We multiply parentheses

x+5x-(3(x+2)-2)+20=0



We calculate terms in parentheses: -(3(x+2)-2), so:

3(x+2)-2

We multiply parentheses

3x+6-2

We add all the numbers together, and all the variables

3x+4

Back to the equation:

-(3x+4)



We add all the numbers together, and all the variables

6x-(3x+4)+20=0

We get rid of parentheses

6x-3x-4+20=0

We add all the numbers together, and all the variables

3x+16=0

We move all terms containing x to the left, all other terms to the right

3x=-16

x=-16/3

x=-5+1/3

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