5(x+4)-2x=6(12-x)+3x+2

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Solution for 5(x+4)-2x=6(12-x)+3x+2 equation: 



5(x+4)-2x=6(12-x)+3x+2

We move all terms to the left:

5(x+4)-2x-(6(12-x)+3x+2)=0

We add all the numbers together, and all the variables

5(x+4)-2x-(6(-1x+12)+3x+2)=0

We add all the numbers together, and all the variables

-2x+5(x+4)-(6(-1x+12)+3x+2)=0

We multiply parentheses

-2x+5x-(6(-1x+12)+3x+2)+20=0



We calculate terms in parentheses: -(6(-1x+12)+3x+2), so:

6(-1x+12)+3x+2

We add all the numbers together, and all the variables

3x+6(-1x+12)+2

We multiply parentheses

3x-6x+72+2

We add all the numbers together, and all the variables

-3x+74

Back to the equation:

-(-3x+74)



We add all the numbers together, and all the variables

3x-(-3x+74)+20=0

We get rid of parentheses

3x+3x-74+20=0

We add all the numbers together, and all the variables

6x-54=0

We move all terms containing x to the left, all other terms to the right

6x=54

x=54/6

x=9

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