5(x+4)-5=4(x-3)+2(3x-1)

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Solution for 5(x+4)-5=4(x-3)+2(3x-1) equation: 



5(x+4)-5=4(x-3)+2(3x-1)

We move all terms to the left:

5(x+4)-5-(4(x-3)+2(3x-1))=0

We multiply parentheses

5x-(4(x-3)+2(3x-1))+20-5=0



We calculate terms in parentheses: -(4(x-3)+2(3x-1)), so:

4(x-3)+2(3x-1)

We multiply parentheses

4x+6x-12-2

We add all the numbers together, and all the variables

10x-14

Back to the equation:

-(10x-14)



We add all the numbers together, and all the variables

5x-(10x-14)+15=0

We get rid of parentheses

5x-10x+14+15=0

We add all the numbers together, and all the variables

-5x+29=0

We move all terms containing x to the left, all other terms to the right

-5x=-29

x=-29/-5

x=5+4/5

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