5(x+4)-x=2(3-x)-10

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Solution for 5(x+4)-x=2(3-x)-10 equation: 



5(x+4)-x=2(3-x)-10

We move all terms to the left:

5(x+4)-x-(2(3-x)-10)=0

We add all the numbers together, and all the variables

5(x+4)-x-(2(-1x+3)-10)=0

We add all the numbers together, and all the variables

-1x+5(x+4)-(2(-1x+3)-10)=0

We multiply parentheses

-1x+5x-(2(-1x+3)-10)+20=0



We calculate terms in parentheses: -(2(-1x+3)-10), so:

2(-1x+3)-10

We multiply parentheses

-2x+6-10

We add all the numbers together, and all the variables

-2x-4

Back to the equation:

-(-2x-4)



We add all the numbers together, and all the variables

4x-(-2x-4)+20=0

We get rid of parentheses

4x+2x+4+20=0

We add all the numbers together, and all the variables

6x+24=0

We move all terms containing x to the left, all other terms to the right

6x=-24

x=-24/6

x=-4

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