5(x+4)/7=2(3x+13)/8

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Solution for 5(x+4)/7=2(3x+13)/8 equation: 



5(x+4)/7=2(3x+13)/8

We move all terms to the left:

5(x+4)/7-(2(3x+13)/8)=0

We calculate fractions


5x/()+(-(2(3x+13)*7)/()=0



We calculate terms in parentheses: +(-(2(3x+13)*7)/(), so:

-(2(3x+13)*7)/(

We multiply all the terms by the denominator


-(2(3x+13)*7)



We calculate terms in parentheses: -(2(3x+13)*7), so:

2(3x+13)*7

We multiply parentheses

42x+182

Back to the equation:

-(42x+182)



We get rid of parentheses

-42x-182

Back to the equation:

+(-42x-182)



We get rid of parentheses

5x/()-42x-182=0

We multiply all the terms by the denominator


5x-42x*()-182*()=0

We add all the numbers together, and all the variables

5x-42x*()=0

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