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5(x+4)=2(2x+5)+6
We move all terms to the left:
5(x+4)-(2(2x+5)+6)=0
We multiply parentheses
5x-(2(2x+5)+6)+20=0
We calculate terms in parentheses: -(2(2x+5)+6), so:We get rid of parentheses
2(2x+5)+6
We multiply parentheses
4x+10+6
We add all the numbers together, and all the variables
4x+16
Back to the equation:
-(4x+16)
5x-4x-16+20=0
We add all the numbers together, and all the variables
x+4=0
We move all terms containing x to the left, all other terms to the right
x=-4
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